Gina Williams always dreamed of performing at the Hollywood Bowl.
Now, the Coquitlam musician has a chance to be at the famous Los Angeles venue to open for a major act.
Williams has until July 21 at 8 p.m. to clinch Opening Act, a competition put on by Audacy (formerly Radio.com) that sees the performer with the most amount of votes play the Hollywood Bowl — and win $10,000.
Last year’s winner opened for Coldplay, Black Eyed Peas, Doja Cat, Kid Laroi and Shawn Mendes at Audacy’s annual concert.
Williams told the Tri-City News, if she’s successful, she’ll donate most of her windfall to charity.
"This would be incredible if I won because I always, always wanted to be on stage at the Hollywood Bowl," she said.
"I think this would give people an opportunity to hear my music."
A classically trained pianist, Williams was busy during the COVID-19 pandemic, releasing five albums in various genres last year.
Currently, Williams is fifth in the contest in a field of about 60 candidates.
Votes can be cast daily for free; however, there is also an optional fundraising component for the American Foundation for Suicide Prevention.
Williams, who starts an artist residency this Sunday (July 17) in Bellingham, is well-known for performing and recording in Ukraine.
This year, she’s hosted five benefit concerts for humanitarian relief in the war-torn country.
To cast a vote for Gina Williams, you're encouraged to visit her website and click on Opening Act.